![]() Our powerful algorithm solves almost any Sudoku puzzle in seconds, allowing you to move on to more challenging puzzles quickly. With Sudoku Solver, you don't have to spend hours solving puzzles by hand. It's a challenging game that helps improve concentration, memory, and cognitive abilities. Sudoku is a popular number-placement puzzle game that requires players to fill a nine-by-nine grid with digits so that each row, column, and 3x3 section contains numbers between 1 and 9, with each number used once and only once in each section. So, this function tells us if there is any unallocated cell or not.Sudoku Solver: A Fun and Challenging Way to Exercise Your Brain!Īre you ready to put your logical thinking and reasoning skills to the test? Look no further than Sudoku Solver, the ultimate tool for solving Sudoku puzzles quickly and easily. In Java and Python, we are returning an array (or list, for Python) which contains these values. ![]() In C, we have used pointers to change the value of the variables (row, col) passed to this function (pass by reference). ![]() Number_unassigned → This function finds a vacant cell and makes the variables ‘row’ and ‘col’ equal to indices of that cell. Print_sudoku() → This is just a function to print the matrix. Thus, the matrix contains the Sudoku problem and the cells with value 0 are vacant cells. Initially, we are just making a matrix for Sudoku and filling its unallocated cells with 0. SIZE = 9 #sudoku problem #cells with value 0 are vacant cells matrix =, ,, ,, ,, , ] #function to print sudoku def print_sudoku (): for i in matrix : print ( i ) #function to check if all cells are assigned or not #if there is any unassigned cell #then this function will change the values of #row and col accordingly def number_unassigned ( row, col ): num_unassign = 0 for i in range ( 0, SIZE ): for j in range ( 0, SIZE ): #cell is unassigned if matrix = 0 : row = i col = j num_unassign = 1 a = return a a = return a #function to check if we can put a #value in a paticular cell or not def is_safe ( n, r, c ): #checking in row for i in range ( 0, SIZE ): #there is a cell with same value if matrix = n : return False #checking in column for i in range ( 0, SIZE ): #there is a cell with same value if matrix = n : return False row_start = ( r // 3 ) * 3 col_start = ( c // 3 ) * 3 #checking submatrix for i in range ( row_start, row_start + 3 ): for j in range ( col_start, col_start + 3 ): if matrix = n : return False return True #function to check if we can put a #value in a paticular cell or not def solve_sudoku (): row = 0 col = 0 #if all cells are assigned then the sudoku is already solved #pass by reference because number_unassigned will change the values of row and col a = number_unassigned ( row, col ) if a = 0 : return True row = a col = a #number between 1 to 9 for i in range ( 1, 10 ): #if we can assign i to the cell or not #the cell is matrix if is_safe ( i, row, col ): matrix = i #backtracking if solve_sudoku (): return True #f we can't proceed with this solution #reassign the cell matrix = 0 return False if solve_sudoku (): print_sudoku () else : print ( "No solution" ) Explanation of the code #include #define SIZE 9 //sudoku problem int matrix = Python If there is no digit which fulfills the need, then we will just return false as there is no solution of this Sudoku.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |